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5n^2=280-5n
We move all terms to the left:
5n^2-(280-5n)=0
We add all the numbers together, and all the variables
5n^2-(-5n+280)=0
We get rid of parentheses
5n^2+5n-280=0
a = 5; b = 5; c = -280;
Δ = b2-4ac
Δ = 52-4·5·(-280)
Δ = 5625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{5625}=75$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-75}{2*5}=\frac{-80}{10} =-8 $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+75}{2*5}=\frac{70}{10} =7 $
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